a driver takes 0.2s to apply brakes when he sees a need for it . if he is driving at a speed of 54km/h and the brakes cause retardation of 6m/s ? find distance travelled by car after he less the need to put the break ?
Asked by | 18th Sep, 2011, 12:00: AM
Here, u = 54 km/hr =15 m/s , v =0, t = 0.2 s, a = - 6 m/s, s =?
Using, s = ut + (1/2) at2 , and plogging in the values we get:
s = (15 x 0.2 ) + (1/2) (-6) (0.2)2
s = 3 - 0.12 = 2.88 m
Answered by | 19th Sep, 2011, 01:16: PM
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