a current of 1.6 mA flows through a conductor. if charge on an electron is -1.6 × 10^-19 Coulomb , find the number of electrons that will pass each second through the cross section of that conductor.

Asked by nagarajpandu | 1st Jan, 2019, 12:34: AM

Expert Answer:

As we know from properties of chargers that charge is quantised 
So Q = It
Q= 1.6 ×10^-3 ×1= 1.6×10^-3
Again Q = ne 
1.6×10^-3= n ×1.6×10^-19
n = 10^16
So there is 10^16 number of electrons passing in one second. 

Answered by Ankit K | 1st Jan, 2019, 09:38: PM