a current of 1.6 mA flows through a conductor. if charge on an electron is -1.6 × 10^-19 Coulomb , find the number of electrons that will pass each second through the cross section of that conductor.
Asked by nagarajpandu | 1st Jan, 2019, 12:34: AM
As we know from properties of chargers that charge is quantised
So Q = It
Q= 1.6 ×10^-3 ×1= 1.6×10^-3
Again Q = ne
1.6×10^-3= n ×1.6×10^-19
n = 10^16
So there is 10^16 number of electrons passing in one second.
Answered by Ankit K | 1st Jan, 2019, 09:38: PM
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