a cricketer can throw a ball to a maximum horizontal distance of 100 m.how much high above the

Asked by  | 24th Jul, 2009, 03:46: PM

Expert Answer:

We know that horizontal range is maximum if the angle of projection is 45o and is given by

Rmax = u2 / g

Here, Rmax = 100 m

so, u2 / g  = 100 m

If the cricketer throws the ball vertically upwardthen the ball will attain the maximum height from the ground

Hmax = u2 / 2g  = 100 /2 = 50 m.

Answered by  | 25th Jul, 2009, 06:39: PM

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