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A CORK OF DENSITY 0.15 GCM-3FLOATS IN WATER WITH 10CM3 OF ITS VOLUME ABOVE THE SURFACE OF WATER.CALCULATE THE MASS OF THE CORK.
Asked by M.s.srinidhi21 | 09 Oct, 2014, 05:03: PM
answered-by-expert Expert Answer
begin mathsize 14px style Given : Density space Of space Crok comma space straight rho subscript straight c equals 0.15 space straight g divided by cm cubed Density space of space water comma space straight rho subscript straight w equals 1 space straight g divided by cm cubed Volume space of space crok space straight V subscript straight c equals 10 space cm cubed By space the space principle space of space floatation ; straight V subscript straight c cross times space straight rho subscript straight c cross times straight g equals space straight rho subscript straight w cross times space straight V subscript straight w cross times straight g rightwards double arrow fraction numerator straight V over denominator space straight V subscript straight w end fraction equals fraction numerator straight V subscript straight c plus straight V subscript straight w over denominator space straight V subscript straight w end fraction equals straight V subscript straight c over straight V subscript straight w plus 1 equals fraction numerator space straight rho subscript straight w over denominator space straight rho subscript straight c end fraction straight V subscript straight w equals fraction numerator space straight rho subscript straight c over denominator space straight rho subscript straight w minus space straight rho subscript straight c end fraction straight V subscript straight c mass space of space crock equals space straight rho subscript straight c left parenthesis straight V subscript straight c plus straight V subscript straight w right parenthesis equals straight rho subscript straight c open parentheses 1 plus fraction numerator space straight rho subscript straight c over denominator space straight rho subscript straight w minus space straight rho subscript straight c end fraction close parentheses straight V subscript straight c equals fraction numerator space straight rho subscript straight c space straight rho subscript straight w over denominator space straight rho subscript straight w minus space straight rho subscript straight c end fraction straight V subscript straight c straight m equals fraction numerator 0.15 cross times 1 over denominator 1 minus 0.15 end fraction cross times 10 equals 1.765 space straight g Hence space mass space of space the space crock space is space 1.765 space straight g end style
Answered by Priyanka Kumbhar | 09 Oct, 2014, 07:10: PM

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