A copper wire of length 2.2m and a steel wire of length 1.6m,both of diameter 3.0mm, are connected end to end, when stretched by a load, the net elongation is found to be 0.70mm .obtain the load applied.

Asked by Jisha Mary Thomas | 16th Oct, 2013, 06:11: PM

Expert Answer:

Length of copper wire Lc= 2.2 m

Length of steel wire Ls = 1.6 m

Diameter d = 3 mm = 3 × 10–3 m

Cross sectional are =

 

                          

Net elongation (lc + ls) = 0.70 mm = 7 × 10–4 m    ....(1)

Let load applied is F.

Ys = 2.0 × 1011 N/m2

Tc = 1.3 × 1011 N/m2

 

Apply (2) and (3)

 

Plug in the values

 

From (1) and (4)

 

From Equation (2)

 

 

Answered by Faiza Lambe | 16th Oct, 2013, 10:03: PM

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