A copper wire has a diameter of 0.5 mm and resistivity 0f 1.6 ohm-cm. how much of this wire would be

Asked by  | 10th Aug, 2009, 01:54: PM

Expert Answer:

Let the length required be l.

 Now using the relation,R=(Resistivity)(l/A)

10=1.6 *(l/(3.14*(0.25*10-3 )2 )

Hence l=1.22*10-6 m

Answered by  | 10th Aug, 2009, 02:02: PM

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