CBSE Class 12-science Answered
A converging lens of refractive index 1.5 and of focal length 15 cm in air, has the same radii of curvature for both sides. if it is immersed in a liquid of refractive index 1.7, Calculate the focal length of the lens in the liquid?
Asked by satya785583 | 24 Mar, 2019, 10:58: AM
Expert Answer
Refractive index of the lens material, aμg =1.5
Focal length of the lens in air, fair = 15 cm
Using lens makers formula-
1/fair = (aμg-1) [1/R1 -1/R2]
1/15 = (1.5-1)[1/R1 -1/R2]
[1/R1 -1/R2] = 1/7.5
Refractive index of liquid, aμL =1.7
Refractive index of lens glass with respect to liquid, Lμg=aμg /aμL
Lμg= 1.5/1.7 = 0.88
Let the focal length of the lens in liquid is-
1/fliquid = (Lμg-1)[1/R1 -1/R2]
1/fliquid = (0.88-1)[1/7.5]
= -0.015
So,fliquid = -66.67 cm.
Answered by Ankit K | 24 Mar, 2019, 10:18: PM
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