A compound of emperical formula CH2O has a VDof 30 write down its molecular formula.

 

Asked by yajay0441 | 27th Aug, 2018, 03:15: PM

Expert Answer:

Given:
 
Emperical formula = CH2O
 
Vapour density = 30
 
Emperical formula weight = 12+2+16
 
                                      = 30
 
Molecular weight = Vapour density×2
 
                          = 2×30
 
                          = 60
 
straight n equals fraction numerator Molecular space weight over denominator Empirical space formula space weight end fraction

space space space equals 60 over 30

space space space equals 2

Molecular space formula space is space open parentheses CH subscript 2 straight O close parentheses subscript 2

space Molecular space formula space is space straight C subscript 2 straight H subscript 4 straight O subscript 2 space space space space space space space space space space space space space space space space space space space space space space space space space space space
 
Molecular formula is C2H4O2.

Answered by Varsha | 27th Aug, 2018, 05:53: PM