A coil having N turns is wound tightly in the form of a spiral with inner and outer radii a and b respectively.when a current I passes through the coil,the magnetic field at the centre is?

Asked by Gaurav Avhad | 29th Oct, 2010, 02:16: PM

Expert Answer:

Dear student
 
The expression for magnetic field at the centre of a toroidal coil through which current 'i' is flowing is :
 
B = µo N i / 2∏ r ; here r = (a + b )/2
 
We hope this clarifies your doubt.
 
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Answered by  | 30th Oct, 2010, 07:44: PM

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