CBSE Class 11-science Answered
A clay was dried partially and it contained 50% silica and 7% water. The original clay contained 12% water. What is the percentage of silica in the original sample?
Asked by Prince Sonu | 18 Apr, 2013, 09:21: PM
Expert Answer
Consider 100g of the partially dried clay sample:
It contains :
7g water
50g silica
43g other things.
Total non water component: 93g
Original clay sample contained:
12g water
The total non- water components must have had mass 88g, BUT in the same proportion as above:
Mass Silica = 50/93*88 = 47.3g
Mass other things = 43/93*88 = 40.7g
% composition of original sample :
Water: 12%
Silica: 47.3%
Other things: 40.7%
It contains :
7g water
50g silica
43g other things.
Total non water component: 93g
Original clay sample contained:
12g water
The total non- water components must have had mass 88g, BUT in the same proportion as above:
Mass Silica = 50/93*88 = 47.3g
Mass other things = 43/93*88 = 40.7g
% composition of original sample :
Water: 12%
Silica: 47.3%
Other things: 40.7%
Answered by | 19 Apr, 2013, 08:57: PM
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