A clay ball of mass m and speed v strikes another metal ball of the same mass m, which is at rest. They stick together after collision. The kinetic energy of the system after collision is what?
Asked by
| 11th Nov, 2012,
12:06: AM
Expert Answer:
By conservation of linear momentum,
momentum before collision =momentum after collision
mv = 2m v
v =v/2
Final kinetic energy, KEf =(1/2)x(2m)x (v)2 =(mv2) /4
Answered by
| 12th Nov, 2012,
01:10: AM
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