A clay ball of mass m and speed v strikes another metal ball of the same mass m, which is at rest. They stick together after collision. The kinetic energy of the system after collision is what?

Asked by  | 11th Nov, 2012, 12:06: AM

Expert Answer:

By conservation of linear momentum,
momentum before collision =momentum after collision
                                     mv = 2m v’
                                  v’ =v/2
 Final kinetic energy,         KEf =(1/2)x(2m)x (v’)2 =(mv2) /4

Answered by  | 12th Nov, 2012, 01:10: AM

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