A cistern 6m long ,4mwide, contains water to a depth of 1m 25m , find the area of the wet surface.

 

Asked by sonukushgzp | 19th Aug, 2019, 11:12: AM

Expert Answer:

Let l and b be the length and breadth.
l = 6 m
b = 4 m
Using the formula , 

Area of the wet surface, 

= [2(lb + bh + lh) - lb] 

= 2(bh + lh) + lb 

= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] 

= 49m2.

Answered by Sneha shidid | 19th Aug, 2019, 01:29: PM