A circular disc of radius 2 m is revolving at 240 revolutions per minute. A torque is applied which slows it at constant rate of (pie) radian/sec 2. In what time the disc will completely stop. Ans. 8 sec.
Asked by | 15th Oct, 2013, 10:47: PM
We have the kinematic equation v = u + at, for circular motion as;
? = ?0 + ?t
Here, the torque is acting to stop the disc. Hence, angular acceleration is negative, that is, ? = -? rad/s2.
Thus, we have
Answered by Romal Bhansali | 17th Oct, 2013, 10:37: AM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number