a chemist has one solution which is 50% acid and a second solution which is
Asked by mehaksaini | 10th Feb, 2010, 01:32: PM
Let X be the amount of first solution and Y be the amount of second to be taken.
The amount of acid in X = 0.5X
But another 50% has to be water.
The amount of water = 0.5X.
The amount of acid in Y = 0.25Y
The amount of water in Y = 0.75Y
The total amount of acid required in final solution = 0.4x10 = 4 lit and remaining 6 lit would be water.
0.5X + 0.25Y = 4 .............(1)
Similarly for water,
0.5X + 0.75Y = 6 .................(2)
Solving (1) and (2), gives,
Y = 4 lit and X = 6 lit.
6 lit of first solution and 4 lit of second solution should be taken.
Answered by | 10th Feb, 2010, 01:59: PM
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