CBSE Class 12-science Answered
A charged Particle, proton, moves between the p.d of 'V'and enters into the perpendicular uniform electric field of strength E, extended upto distance X. what is the expression for deflection of the charged particle when it is just out of the electric field region.
Asked by | 03 Aug, 2012, 08:04: AM
Expert Answer
Let the particle enters with speed= v
AB will be the trajectory, it will follow. at point A, it will have velocity v in x direction, acceleration in x direction=ax=0 and acceleration in y direction=ay=eE/m=eV/mx, as the particle will get accelerated towards the field.
so the distance covered in x direction:
x=uxt+1/2 ax t2 =vt
so t=x/v
distance covered in y direction: b=uyt+1/2 ay t2 =(1/2)( eV/x) t2 =eVx/2mv2 , putting value of t.
Answered by | 19 Nov, 2012, 03:19: PM
Concept Videos
CBSE 12-science - Physics
Asked by am1954077 | 08 Mar, 2024, 04:57: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by rishabhverma895334 | 01 Mar, 2024, 07:24: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by rameshsanju123 | 08 Feb, 2024, 08:45: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by sachin.sondur2012 | 07 Feb, 2024, 11:26: AM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by millionairekishan | 25 Jan, 2024, 12:34: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by kalsichaitanya | 30 Dec, 2023, 04:08: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by mahantabibhutibhusan261 | 06 Nov, 2023, 09:04: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by glorialyanzaw | 13 Oct, 2023, 05:53: PM
ANSWERED BY EXPERT
CBSE 12-science - Physics
Asked by manishakumariroy321 | 10 Oct, 2023, 09:02: PM
ANSWERED BY EXPERT