A charge Q is placed at the centre of a cube of side L .what is the flux passing through each face of the cube?
Asked by babita bhatt | 17th Feb, 2014, 10:13: PM
Expert Answer:
According to Gauss’ Theorem, the total electric flux through all the six faces of the cube is,
φ = Charge enclosed / ε 0
φ = q /ε 0
Each face of the cube comprises 1/6 of the total surface of the cube. Therefore, the flux passing through each face is,
φ = 1/6 ? q/ε 0 = q /6 ε 0
According to Gauss’ Theorem, the total electric flux through all the six faces of the cube is,
φ = Charge enclosed / ε 0
φ = q /ε 0
Each face of the cube comprises 1/6 of the total surface of the cube. Therefore, the flux passing through each face is,
φ = 1/6 ? q/ε 0 = q /6 ε 0
Answered by | 18th Feb, 2014, 12:32: PM
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