A car of mass 2 kg is moving with speed of 10m/s.  Calculate work done to stop it ?

Asked by atiquzzaman100 | 21st Oct, 2021, 01:35: PM

Expert Answer:

By work-energy theorem , workdone on a body is equal to change in kietic energy.
 
If the car of mass 2 kg ( toy car ! ) moving with speed 10 m/s , then its kinetic enrgy K is given as
 
K = (1/2) m v2 = (1/2) × 2 × 10 × 10 = 100 J
 
If the car is to be stopped , then change in kinetic energy = 100 J
 
hence, workdone to stop the car = 100 J

Answered by Thiyagarajan K | 21st Oct, 2021, 01:50: PM