A car is traveling along a circular curve that has a radius of 42.67 m . If it's speed is 16m/s and is increasing uniformly at 8m/s^2 . The magnitude of net acceleration at this instant is 

Asked by arunavamitra50 | 9th Jul, 2018, 06:05: PM

Expert Answer:

Net acceleration begin mathsize 12px style a subscript T space equals space square root of a subscript r superscript 2 plus space a subscript t superscript 2 end root end style
where begin mathsize 12px style a subscript r space end subscript equals space R a d i a l space A c c e l e r a t i o n space equals space v squared over R end style and at is tangential acceleration
v is tangential velocity and R is radius of curvature.
 
v(t) = 16+8×t , begin mathsize 12px style a subscript r space equals space fraction numerator open parentheses 16 plus 8 t close parentheses squared over denominator 42.67 end fraction end style , hence begin mathsize 12px style a subscript T space equals space square root of open parentheses 16 plus 8 t close parentheses to the power of 4 over open parentheses 42.67 close parentheses squared plus 64 end root space space end style m/s2

Answered by Thiyagarajan K | 14th Jul, 2018, 06:01: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.