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CBSE Class 9 Answered

A car is coasting backwards down a hill at -3.0 m/s when the driver gets the engine started. After 2.5s, the car is moving uphill at a velocity of +4.5 m/s. What is the car's acceleration?  
Asked by vijayparmar555115 | 01 May, 2020, 03:03: PM
answered-by-expert Expert Answer
Given :
u = - 3 m/s
v = +4.5 m/s
t = 2.5 s 
a=?
 
According to first equation of motion,
v=u +at 
 
Thus,
 
4.5 =(-3) + a(2.5)
 
4.5 +3 = a(2.5)
7.5 = a(2.5)
 
a = 7.5/2.5 = 3 m/s2 
 
Thus, car's acceleration is 3 m/s2 .
 
Answered by Shiwani Sawant | 01 May, 2020, 03:21: PM
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