A car is coasting backwards down a hill at -3.0 m/s when the driver gets the engine started. After 2.5s, the car is moving uphill at a velocity of +4.5 m/s. What is the car's acceleration?
Asked by vijayparmar555115 | 1st May, 2020, 03:03: PM
Expert Answer:
Given :
u = - 3 m/s
v = +4.5 m/s
t = 2.5 s
a=?
According to first equation of motion,
v=u +at
Thus,
4.5 =(-3) + a(2.5)
4.5 +3 = a(2.5)
7.5 = a(2.5)
a = 7.5/2.5 = 3 m/s2
Thus, car's acceleration is 3 m/s2 .
Answered by Shiwani Sawant | 1st May, 2020, 03:21: PM
Related Videos
- what is nth second of motion
- A car starts from the rest and accelerates at the rate of 5m/s2. It continue accelerating for 10 s and then move at constant velocity for next 10 s. Calculate the total distance traveled by the car in 20s. (5)
- Problems and solutions on kinematics, Horizontal motion
- Please solve it with method
- Derivation of the three equation s of motion
- In derivation of the second equation of motion which side denotes acceleration
- Prove that if a body is thrown vertically upward the time of ascent is equal to the time of descent
- A ball is thrown vertically words from ground when it is at three fourth of its maximum height its speed is 20 metre per second the speed of throw is
- What is the 1st equation of motion
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change