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A car  initially at rest picks up a velocity of 72 km per hour in 20 seconds if the mass of the car is 1000 kg find Force developed by its engine and distance covered by car

Asked by Samrat | 29 Jun, 2018, 10:26: PM
speed = 72 km/hr = 72×(5/18) = 20 m/s
acceleration a is obtained from the formula " v = u + a×t " ,
with initial speed u = 0 and final speed v = 20 m/s. t is time taken, 20 s.

a = v/t = 20/20 = 1 m/s2

Force = mass×acceleration = 1000×1 = 1000 N

distance  travelled  S is obtained from formula " S = u×t+(1/2)×a×t2 " , with u =0, t =20 s

S = (1/2)×1×20×20 = 200 m
Answered by Thiyagarajan K | 30 Jun, 2018, 01:27: PM

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