CBSE Class 9 Answered
A car accelerates uniformly from 18km to 36km h in 5s calculate the acceleration and the distance covered by the car in that time.
Asked by shobhavittal.sv | 30 Jul, 2019, 07:45: PM
Initial speed = u = 18 km/hr = 5 m/s
Final sped = v = 36 km/hr = 10 m/s
acceleration a = (v-u)/t = (10-5)/5 = 1 m/s2
Distance travelled S = u t + (1/2) a t2 = 5×5 + (1/2)×1×52 = 37.5 m
Answered by Thiyagarajan K | 31 Jul, 2019, 07:58: AM
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