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A candidate scored 25% marks in an examintion and was failed by 30 marks,while another candidate scored 50% marks and got 20 marks more than the minimum pass marks.find the maximum and the minimum pass marks
Asked by kenikaria | 27 Nov, 2018, 09:49: PM
Let maximum mark be x and minimum mark be y.

25% of maximum mark = (25/100)x = x/4 = y-30 ..............(1)
50% of maximum mark = (50/100)x = x/2 = y+20 ...........(2)

subtract eqn.(1) from eqn.(2), we get    x/4  = 50  or  x = 200

substituting value of x in eqn.(1), we get y = 80

hence maximum mark is 200 and minimum mark is 80
Answered by Thiyagarajan K | 27 Nov, 2018, 10:28: PM

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