a bullet of mass 5g travels with a speed of 500m/s . if it penetrates a fixed target if it offers a constant resistant force to the motion of the bullet . find the initial K.E of bullet distance through which bullet has penetrated ?
Asked by ayush kumar | 23rd Jan, 2011, 07:20: PM
K.E = 1/2 m v ^2
= 0.5X0.005X500X500 = 625J
Hope this helps.
Please get back to us for any queries.
Answered by | 2nd Feb, 2011, 01:22: PM
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Verify mobile number
Enter the OTP sent to your number