a bullet of mass 50g is moving with a velocity of 500m/s. it penetrates 10cm into a still target and comes to rest. calculate a. the kinetic energy possessed by the bullet b. the average retarding force offered by the target.
Asked by | 28th Dec, 2011, 12:00: AM
Expert Answer:
Here, m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0, KE = ?, F = ?
(i) KE = 1/2mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.
(ii) Using v2 u2 = 2aS, we get
a = {v2 u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}
= 1250000ms-2.
Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N.
Here, m = 50 g = 50 × 10-3 kg, u = 500 ms-1, s = 10 cm, v = 0, KE = ?, F = ?
(i) KE = 1/2mv2 = 1/2×50 × 10-3 × (500)2 = 6250 J.
(ii) Using v2 u2 = 2aS, we get
a = {v2 u2}/{2aS} = {02 (500)2}/{2 × 10 ×10-2}
= 1250000ms-2.
Therefore, retarding force, F = ma = 50 × 10-3 × 1250000 = 62500 N.
Answered by | 29th Dec, 2011, 12:57: PM
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