a bullet of mass 10g travelling horizontally with a velocity of 150ms-1 strikes a stationary wooden block and comes to rest in 0.03sec. calculate the distance of penetration of he bullet into the block. also calculate the magnitude of the force exerted by the wooden block on the bullet
Asked by praju99 | 17th Aug, 2010, 12:00: AM
KE = (1/2) (10/1000) 1502 = 112.5 J.
Deceleration of the bullet, = initial velocity - final velocity / time = 150/0.03 = 5000 m/s2.
Force = Mass x Acceleration = (10/1000)(5000) = 50 N.
Distance = Work done/force = Energy/force = 112.5/50 = 2.25 m
Answered by | 17th Aug, 2010, 11:03: PM
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