A bullet loses 1/20th of its velocity after passing through a plank . How many planks it can pass so
Asked by
| 3rd Oct, 2008,
08:39: AM
Expert Answer:
let the length of the plank be x
using v^2 = u^2 + 2aS find the value of v.
v = u-(1/20)u =19/20u
Find a
a = 39/800 (u^2/x)
Now for bullet to stop completely, v = 0
0 = u^2 -39/800 (u^2/x).S
s=800/39x which means approximately 20.5 planks
Answered by
| 11th Dec, 2008,
09:44: AM
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