A BULLET FIRED INTO A BLOCK LOSES HALF ITS VELOCITY AFTER MOVING 0.9m BEFORE IT COMES TO REST, DISTANCE TRAVELLED WOULD BE ? ITS MCQ OPTIONS ARE 1.2m 0.8m 2.0m 1.6m
Asked by shreya | 27th Oct, 2013, 08:35: PM
The bullet loses half its velocity after penetrating 0.9 m into the target.
Let us say that the gun fires the bullet with force F.
The work done by the gun goes as change in kinetic energy of the bullet.
Thus, work done after penetrating 0.9 m inside the target is
F × (0.9 m) = ½mv2 - ½m(v/2)2 = 3/8 mv2
Thus, we have
mv2 = 2.4F
Now, when the bullet penetrates further distance x, the entire kinetic energy is lost. Thus, we have
F × (0.9 + x m) = ½mv2
Thus, the total distance S penetrated by the bullet inside the target is,
Answered by Romal Bhansali | 28th Oct, 2013, 10:03: AM
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