a bulb of unknown volume V contains a gas at 1 atm pressure. this bulb was connected to another evacuated bulb of volume 0.5 L through a stop cock. when the stop cock was opened, the pressure at each bulb becomes 7.58*10 raise to power 5 Pa while the temperature remained constant. calculate V in litres.

Asked by ABHINAVSINGH | 5th Jun, 2013, 06:30: PM

Expert Answer:

1 atm = 101325 Pa

P1V1 = P2V2

101325 x V = 7.58 x 104 x (V + 0.5)

101325V - 75800V = 37900

V = 37900/25525

V = 1.48 L

Answered by  | 6th Jun, 2013, 10:52: AM

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