Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

A boy swimming comes out from a pool covered with a film of water weigh 18g.how much heat must be supplied to evaporate this water at 298K .calculate the internal energy of vaporisation at 100C .the enthalpy change of vapourisation for water ta 373K=40.66 kJ/mol
Asked by | 05 Oct, 2013, 08:34: AM
answered-by-expert Expert Answer
18 g water = 1 mole water. The temp. is 298K. To raise the temp. to bp (373K), it absorbs 18 x (373 -298) cal (=18 x 4.185 x (373 -298)J) heat and another 40660 j to Liquid --> vapour phase. Sum = [18x4.185{373 - 298} +40660] x (1/1000)kJ.
Answered by | 05 Oct, 2013, 04:00: PM
CBSE 11-science - Chemistry
Asked by rukayabatool395 | 24 Mar, 2024, 07:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by mankdubey670 | 06 Jun, 2022, 01:27: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by rama26516 | 12 Mar, 2022, 01:49: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by advssdrall | 11 Jan, 2022, 07:44: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by mossewalasindhu | 20 Nov, 2021, 02:16: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by chandankumargochhayat6 | 19 May, 2021, 08:48: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by paulnaveed202 | 17 Dec, 2020, 12:36: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by kjay0981 | 13 Dec, 2020, 03:45: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Chemistry
Asked by adityasolanki7773 | 22 Oct, 2020, 03:40: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×