A boy pushes a 5.00 kg cart in a circle, starting at 0.500 m/s and accelerating to 3.00 m/s. How much work was done on the cart?

Asked by  | 13th Mar, 2012, 03:52: PM

Expert Answer:

Work done, W by the boy on the cart = increase of kinetic energy of the cart. So W is given by
W = 0.5*5.00*[3.00^2 - 0.500^2] = 21.875 J or 21.9 J. Boy in addition will have to work against friction too

Answered by  | 14th Mar, 2012, 11:47: AM

Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working day.