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a box contains 90 discs which are numbered from 1to90. if one disc is drawn at random from the box, find the probablity that it bears a box contains 90 discs which are numbered from 1to90. if one disc is drawn at random from the box, find the probablity that it bears 1.a two digit number
Asked by Rutuja Mehta | 09 Oct, 2013, 08:24: PM
answered-by-expert Expert Answer
Out of 90 discs, in the box, one disc can be drawn in 90 ways.
Therefore, total number of elementary events = 90
From numbers 10 to 90, there are 81 two digit numbers. 
Number of Favourable elementary events = number of two digit numbers between 1 to 90
That is n(E)=81     
Hence required probability
Answered by Vimala Ramamurthy | 09 Oct, 2013, 10:43: PM

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