A BOUNCING TENNIS BALL REBOUNDS EACH TIME TO A HEIGHT ONE HALF THAT OF THE PREVIOUS ONE.IF IT IS DROPPED FROM A HEIGHT OF 3m,THE TOTAL DISTANCE TRAVELLED BY THE BALL BEFORE COMING TO REST IS-
Asked by architsrivastava02 | 3rd Mar, 2011, 08:49: PM
Expert Answer:
Dear student,
distance of 1st bounce = 3m
distance of 2nd bounce = 1.5m
distance of 3rd bounce = 0.75m
distance of 4th bounce = 0.37m
distance of 5st bounce = 0.18m
distance of 6th bounce = 0.09m
distance of 7th bounce = 0.04m
distance of 8th bounce = 0.02m
distance of 9th bounce = 0.01m
total distance travelled = 5.69m
check with this:
3 + 2(3)(0.5)(0.5^9 -1)/(0.5-1)
Thanking you
Team
Topperlearning.com
distance of 1st bounce = 3m
distance of 2nd bounce = 1.5m
distance of 3rd bounce = 0.75m
distance of 4th bounce = 0.37m
distance of 5st bounce = 0.18m
distance of 6th bounce = 0.09m
distance of 7th bounce = 0.04m
distance of 8th bounce = 0.02m
distance of 9th bounce = 0.01m
total distance travelled = 5.69m
check with this:
3 + 2(3)(0.5)(0.5^9 -1)/(0.5-1)
Thanking you
Team
Topperlearning.com
Answered by | 7th Mar, 2011, 02:08: PM
Related Videos
Kindly Sign up for a personalised experience
- Ask Study Doubts
- Sample Papers
- Past Year Papers
- Textbook Solutions
Sign Up
Verify mobile number
Enter the OTP sent to your number
Change