A BOUNCING TENNIS BALL REBOUNDS EACH TIME TO A HEIGHT ONE HALF THAT OF THE PREVIOUS ONE.IF IT IS DROPPED FROM A HEIGHT OF 3m,THE TOTAL DISTANCE TRAVELLED BY THE BALL BEFORE COMING TO REST IS-
Asked by architsrivastava02
| 3rd Mar, 2011,
08:49: PM
Expert Answer:
Dear student,
distance of 1st bounce = 3m
distance of 2nd bounce = 1.5m
distance of 3rd bounce = 0.75m
distance of 4th bounce = 0.37m
distance of 5st bounce = 0.18m
distance of 6th bounce = 0.09m
distance of 7th bounce = 0.04m
distance of 8th bounce = 0.02m
distance of 9th bounce = 0.01m
total distance travelled = 5.69m
check with this:
3 + 2(3)(0.5)(0.5^9 -1)/(0.5-1)
Thanking you
Team
Topperlearning.com
distance of 1st bounce = 3m
distance of 2nd bounce = 1.5m
distance of 3rd bounce = 0.75m
distance of 4th bounce = 0.37m
distance of 5st bounce = 0.18m
distance of 6th bounce = 0.09m
distance of 7th bounce = 0.04m
distance of 8th bounce = 0.02m
distance of 9th bounce = 0.01m
total distance travelled = 5.69m
check with this:
3 + 2(3)(0.5)(0.5^9 -1)/(0.5-1)
Thanking you
Team
Topperlearning.com
Answered by
| 7th Mar, 2011,
02:08: PM
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