A body thrown vertically upwards from top of a building reaches the foot of the building in 5 sec;but it will take only 2 secif thrown vertically down with the same velocity.Calculate the height of the building.Given g=9.8m/sec^2.
Asked by Benjamin | 19th Sep, 2015, 05:43: PM
Suppose that the object is thrown with velocity u from the top of the building of height h.
When the object is thrown vertically upwards:
Initial velocity = -u ; a = g ; distance covered = h and t1 = time taken by the object to reach the foot of the building
When the object is thrown vertically downwards:
Initial velocity = u ; a = g ; distance covered = h and t2 = time taken by the object to reach the foot of the building
Dividing equation (1) and (2), we get
Thus, the height of the building is 49 m.
Answered by Yashvanti Jain | 20th Dec, 2017, 07:35: PM
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