A body thrown vertically up with initial velocity 52 m/s from the ground  passes twice a point at h height above at an interval of 10 s . Find the height h where g is given to be 10 m/s square .

 

 

Given that the body is thrown up with initial velocity , u = 52 m/s

it passes twice a point of height h in t= 10 sec.

Therefore :

As it passes twice a point of height H , we can write S =2 h = 20 m

2 h = 20 m

h = 10 m

The height h= 10 m