A body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at h height above at an interval of 10 s . Find the height h where g is given to be 10 m/s square .
Asked by Sayoni Maiti | 3rd Jun, 2014, 06:08: PM
Given that the body is thrown up with initial velocity , u = 52 m/s
it passes twice a point of height h in t= 10 sec.
As it passes twice a point of height H , we can write S =2 h = 20 m
2 h = 20 m
h = 10 m
The height h= 10 m
Answered by Jyothi Nair | 4th Jun, 2014, 09:09: AM
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