A body starting from rest moves with constant acceleration, then the ratio of the distance covered in 5th second to 5 seconds is?

 

 

Let us assume that constant acceleraion to be A.

u = o since the body starts from rest.

and we know that Dispacement in n^th sec = s_nth = s_{upto n} - s_upto(n-1)

[un+(1/2)an²]-[u(n-1)+(1/2)a(n-1)²] 

S_nth=u+(1/2) (2n-1)a

Now,

Distance covered in 5^th second is 

S = 0+1/2 (2 x5-1)a =(9/2)a

 

Distance covered in 5 seconds is

S=ut+(1/2)at²

S=0+(1/2) (ax5x5) = (25/2) xa

Therefore the ratio of the distance covered in 5th second to 5 second is =