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CBSE Class 9 Answered

A body projected vertically upwards crosses point A and B separated by 28m, with velocities one-third and one-fourth of the initial velocity respectively. What is the maximum height reached by it above the ground? Shourya
Asked by Shourya Mukherjee | 10 May, 2012, 10:03: PM
Expert Answer
 
apply, to find initial velocity.
v2-u2=2gs
here we have taken v as initial velocity
v2/16=v2/9  -2x10x 28
v=48?5 m/s
now to find max ht:
v=o at max height
so 0=v-2 x 10 x h
h=576m by putting v=48?5 m/s
 
 
 
 
 
Distance = 576 m
Answered by | 11 May, 2012, 02:40: PM
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