a body of mass 5kg starts and roll down 32m of aninclined plane in 4sec,find the force acting on the body

Asked by kishor.kp14 | 24th Sep, 2019, 11:16: AM

Expert Answer:

Initial velocity u=o, because the body was released
distance travelled= 32m
time=4 seconds
s equals u t plus 1 half a t squared
32 equals 0 cross times 4 plus 1 half cross times a cross times 4 squared
a equals 4 m s to the power of negative 2 end exponent
F o r c e space a c t i n g space a l o n g space t h e space i n c l i n e d space p l a n e equals m a
F equals 5 cross times 4 equals 20 N

Answered by Utkarsh Lokhande | 24th Sep, 2019, 12:48: PM