A body of mass 250g moving on a horizontal rough table.What is the work done if a frictional force is acting on it and brings the body to rest which was initially moving with a speed of 40cm/s?

Asked by anusarika mohanty | 20th Nov, 2013, 06:08: PM

Expert Answer:

Given that,
Mass of the body m = 250 g
Initial velosity u = 40 m/s
Final velosity  v = 0 m/s   (Because body comes at rest)
Work done = change in kinetic energy
Here negative sign denotes the work done in opposite direction of the motion.

Answered by Komal Parmar | 20th Nov, 2013, 06:58: PM

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