A body of mass 200 gm lies on a rough surface whose coefficent of friction are 
s = 0.5 and k = 0.3. A horizontal force F varies as F = t/2 (where F in newton and t in sec ) is applied on body. Calculate -: (g = 10m/s )
- accleration at time t = 1s, 2s, 3s.
- velocity at time t = 3s.
s = 0.5 and k = 0.3. A horizontal force F varies as F = t/2 (where F in newton and t in sec ) is applied on body. Calculate -: (g = 10m/s )- accleration at time t = 1s, 2s, 3s.
- velocity at time t = 3s.
Asked by adityagupta9696
| 10th Oct, 2015,
01:59: PM
Expert Answer:
Dear adityagupta9696@gmail.com
Thanks for asking us a question in Ask the Expert section of TopperLearning.com.
We have not understood the query that you have posted.
You have mentioned that F varies as F = t/2. This equation is dimensionally incorrect as L.H.S is in newtons and R,H.S is in seconds.
Kindly check the quation and post it again so that we may answer this to the best of the ability.
Regards
Topperlearning Team.
We have not understood the query that you have posted.
Regards
Topperlearning Team.
Answered by Romal Bhansali
| 10th Oct, 2015,
04:11: PM
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