A body is thrown up with an initial velocity u and covers a maximum height of h, then h is equal to
Asked by | 29th Dec, 2011, 12:00: AM
Expert Answer:
we know , v2-u2=2as
s=H , v=0m/s and a=-g
hence, -u2=-2gH
so, maximum height attained is
H=u2/2g
Answered by | 29th Dec, 2011, 10:41: PM
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