A body falling from a vertical height of 10 m pierces through a distance of 1 m in sand. Calculate the average retardation in sand faced by the body. ( g= acceleration due to gravity)
a)g
b)9g
c)100g
d)1000g
Asked by Sayoni Maiti
| 5th Jun, 2014,
01:05: AM
Expert Answer:
When the body falls from the height :
u = 0,
s = 10 m ,
Using the equation v2=u2+2as
v2 = 0 + 2g×10
v = √20g
The velocity when it touches the sand is √20g
So when the body pierces through sand : u = √20g, v=0, s = 1 m
v2=u2+2as
0=(√20g)2+2a
-a = 20g / 2
-a = 10 g
The average retardation in sand faced by the body is 10 g
Answered by Jyothi Nair
| 5th Jun, 2014,
10:12: AM
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