a body dropped from the top of a tower falls through 40 m during the last two seconds of its fall.
Asked by | 23rd Jul, 2009, 02:30: PM
Let the h is the height of cliff and stone takes n seconds to reach the ground.
The distance travelled by the particle in nth sec
Snth = u + a ( 2n - 1) / 2
Here, Snth = 40 m , u = 0 , a = 10 m/s2
so, 40 = 10 ( 2n - 1) / 2
or, n = 4.5 sec
So, the stone takes 4.5 s to reach the ground from top of the tower.
Now, the height of the tower
h = ut + gt2 /2
= 0 + 10 (4.5 )2 /2
= 101.25 m
Answered by | 23rd Jul, 2009, 08:23: PM
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