Starting early can help you score better! Avail 25% off on study pack

A block of wood is kept on a table top . The mass of wooden block is 5kg and its dimension are 40cm25cm10cm. Find pressure extended

Asked by srivathchava15 | 14th Mar, 2015, 09:07: PM

Expert Answer:

Given:

Mass of the wooden block= 5 kg

Dimensions = 40 cm x 25 cm x 10 cm

The weight of the wooden block applies a thrust on the top of the table.

Thrust = F = m x g

                = 5 kg x 9.8 m s^-2

                = 49 N

Considering the sides of dimensions,

(a) 25 cm x 10 cm

(b) 40 cm x 25 cm

(a) When the block lies on its sides of dimensions 25 cm x 10 cm

Area of a side = length x breadth

                          = 25 cm x 10 cm = 250 cm²= 0.025 m²

Therefore,

$begin mathsize 14px style Pressure equals Thrust over Area space space space space space space space space space space space space space space equals fraction numerator 49 space straight N over denominator 0.025 space straight m squared end fraction space space space space space space space space space space space space space space space space space equals 1960 space straight N space straight m to the power of negative 2 end exponent end style$

The pressure exerted by 25 cm x 10 cm is 1960 N m^-2.

(b) When the block lies on its sides of dimensions 40 cm x 25 cm

Area of a side = length x breadth

                       = 40 cm x 25 cm = 1000 cm² = 0.1m²

Therefore,

$begin mathsize 14px style Pressure equals Thrust over Area space space space space space space space space space space space space space space equals fraction numerator 49 space straight N over denominator 0.1 space straight m squared end fraction space space space space space space space space space space space space space space equals 490 space straight N space straight m to the power of negative 2 end exponent end style$

The pressure exerted by 40 cm x 25 cm is 490N m^-2.

Answered by Faiza Lambe | 14th Mar, 2015, 10:04: PM

Ask Doubt