A block of mass M moving on the horizontal x-y plane having coefficient of friction mu. The partical has a velocity Vi with overparenthesis on top and acceleration aj with overparenthesis on top . unit vector alond the direction of friction force acting on the particle is 
(a) -i with overparenthesis on top  (b)-j with overparenthesis on top  (c)j with overparenthesis on top   (d) -(i with overparenthesis on top+j with overparenthesis on top )/square root of 2

Asked by Meet Upadhyay | 2nd Aug, 2014, 06:46: PM

Expert Answer:

Let M be the mass of the block,
 
Velocity Vector along x-axis is Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
Acceleration vector along y-axis is Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
the Resultant unit vector is Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '..
since Friction force always opposes the motion hence direction of friction force is opposite to resultant as shown in figure:-
 
 
 
 
Unit vector along the friction force = Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '. = Syntax error from line 1 column 49 to line 1 column 73. Unexpected '<mstyle '.
Correct Ans is option (d)

Answered by Priyanka Kumbhar | 5th Aug, 2014, 04:29: PM