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CBSE Class 12-science Answered

A battery consisting of 10 cells in series has two cells reverse connected by mistake. E.M.F. of each cell is 1.5 V and internal resistance 0.1. The value of external resistance is 4. Find the reduction in current due to the two coils reverse connected.
Asked by Topperlearning User | 04 Jun, 2014, 01:23: PM
answered-by-expert Expert Answer

When the 10 cells are properly connected

                        Total e.m.f. of the battery=n E=10 x 1.5 = 15 V
                        Total circuit resistance    = R + nr = 4+ 10 x 0.1 = 5
                        Circuit current                 = 15 /5 = 3A
 
When two of the cells are reverse connected,
                        Total e.m.f. of the battery= (8 x 1.5) – (2 x 1.5) = 9V
                        Total circuit resistance    = 5 (i.e. the same as before)
                        Circuit current                 = 9 /5 = 1.8A
 
Hence, the reduction in current = 3 -1.8 = 1.2 A
Answered by | 04 Jun, 2014, 03:23: PM

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