a balloon is going up at a steddy velocity of 12m/s at a height of 32m above the ground an object is dropped from it.How long does it take for the object to reach the ground?

Asked by Amitha N | 27th Jan, 2011, 12:00: AM

Expert Answer:

Dear student,
 
Just before hitting the gorund,
 
PE = KE
 
mgh = 1/2 m v^2
 
gh = 1/2
 
9.8 X 32 = 1/2 v^2
 
v^2 = 627.2
v = 25.04 m/s
 
S = d/t
25.04 = 32/t
t = 1.3 sec approx.
 
Hope this helps.
Thanking you
Team
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Answered by  | 27th Jan, 2011, 09:56: PM

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