A BALLOON CONTAIN 5.41 dm cube OF HELIUM AT 24 degree celcius & 101.5 KPa. SUPPOSE THE GAS IN THE BALLOON IS HEATED TO 35 degree celcius , IF THE HELIUM PRESSURE IS NOW 102.8 KPa , WHAT IS THE VOLUME ?

 convert the temperatures to kelvins.T_i = (24 + 273) = 297 K

T_f = (35 + 273) = 308 K

Following is the data table

V_i = 5.41 dm³

P_i = 101.5 kPa

T_i = 297 K

V_f = ?

P_f = 102.8 kPa

T_f = 308 K

Apply both Boyle’s law and Charles’s law combined to get

V_f= V_i x (P_i/P_f) x (T_f/T_i)

V_f=5.41 dm³ *(101.5 kPa/ 102.8 kPa)(308 K/297 K)

V_f=5.54 dm³