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a ball is thrown vertically upwards with avelocity of 49m/s. calculate the max.height to which it rise .
Asked by pramodkumarpv | 12 Oct, 2014, 08:55: PM
answered-by-expert Expert Answer
begin mathsize 14px style straight u equals initial space velocity space of space the space ball equals 49 space straight m divided by straight s straight v equals final space velocity space of space the space ball At space the space maximum space height space the space final space velocity space of space the space ball space is space zero comma space straight i. straight e. comma space straight v space equals space 0. straight s equals height space achieved space by space the space ball equals ? straight g equals acceleration space due space to space gravity equals minus 9.8 ms to the power of minus 2 end exponent According space to space the space equation space of space motion space under space gravity space in space upward space direction space : space space straight v to the power of space 2 end exponent space equals space straight u to the power of space 2 end exponent space plus space 2 space straight g space straight s space straight v space squared space − space straight u to the power of space 2 end exponent space equals space 2 space straight g space straight s space 0 minus left parenthesis 49 right parenthesis squared equals 2 space straight x space left parenthesis minus 9.8 right parenthesis space straight x space straight s straight s equals fraction numerator 49 space straight x space 49 over denominator 2 space straight x space 9.8 end fraction equals 122.5 space straight m Therefore comma space the space maximum space height space attained space by space the space ball space is space 122.5 space straight m. end style
Answered by Faiza Lambe | 12 Oct, 2014, 09:25: PM

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