A ball is thrown vertically upwards with a given velocity 'u' such that it rises for T seconds(T>1), what is the distance travelled by the ball during the last one second of ascent (in metres)? (Acceleration due to gravity is g m/second square)

Asked by adityaahuja099 | 11th Oct, 2017, 07:07: PM

Expert Answer:

 
begin mathsize 16px style Velocity space at space the space toppest space space point space left parenthesis time space straight t right parenthesis space is space zero
therefore space straight v equals straight u minus gt
0 equals straight u minus gt
straight u equals gt
straight t equals straight u over straight g end style
 
begin mathsize 16px style Velocity space at space time space straight t minus 1
straight v equals straight u minus straight g left parenthesis straight t minus 1 right parenthesis
straight v equals gt minus gt plus straight g
straight v equals straight g end style
 
begin mathsize 16px style Distance space traveled space in space last space one space second space left parenthesis straight t equals 1 right parenthesis
straight s equals left parenthesis velcoity space at space time space straight t minus 1 right parenthesis straight t minus 1 half gt squared
equals gx 1 minus 1 half xgx 1 squared
equals straight g over 2 end style

Answered by Gajendra | 27th Nov, 2017, 06:32: PM