a ball is dropped from a height of 10m. if the energy of the ball reduces by 40 percent after striking the ground,how much high the can the ball bounce back
Asked by Shagun Rastogi | 1st Jan, 2014, 11:49: AM
Here, ball has a potential energy due to its height from the floor i.e. mgh = 10m
According to question,
mgh'=mgh x 60/100
(Since ball losses 40% of its energy ,so it is left with 100-40=60% of energy)
Therefore h'=h x (60/100)
=10 x 60/100=6m
Here, ball has a potential energy due to its height from the floor i.e. mgh = 10m
According to question,
mgh'=mgh x 60/100
(Since ball losses 40% of its energy ,so it is left with 100-40=60% of energy)
Therefore h'=h x (60/100)
=10 x 60/100=6m
Answered by Faiza Lambe | 1st Jan, 2014, 07:13: PM
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